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For 𝑎^2+𝑏^2=𝑐^2+𝑑^2
1. If a , b , c and d are different integers then find minimum value of |a+b+c+d|

2. If a , b , c and d are different non negative integers then find minimum value of a+b+c+d

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14 Comments

Comments are closed.

  1. vaibhav kumar 3 years ago

    You are out of the world sir,,,,,main hr time aapki video ka wait krta hu,,,,,,great sir,,,,,

  2. Alok Kumar Singh 3 years ago

    nice one..

  3. Vilas sharma 3 years ago

    Zbra fan

  4. DHIREN KUMAR SAHOO 3 years ago

    Ans1 : 0

  5. RTS Pankaj 3 years ago

    1+8+4+7= 20

  6. Vikash Rakesh 3 years ago

    1# (-1)²+(-2)² = 1² + 2². ; |-1-2+1+2|=0

    2# 3² + 4² = 5² + 0. ; |3+4+5+0|=12

  7. trilochan swain 3 years ago

    1. /-1-2+1+2/=0
    2. 1+8+4+7=20

  8. gaurav singh 3 years ago

    1. -1-2+1+2 ans. 0
    2. 0 3 4 5 ans 12

  9. MALVIKA JHA 3 years ago

    1. -1,-2,1,2,,…value of a,b,c,d nd sum is zero
    2.0,5,3,4…value of a,b,c,d nd sum is 12

  10. sourav joarder 3 years ago

    0 and 20

  11. Vikash Ku mar 3 years ago

    20

  12. swapnil gupta 3 years ago

    1. 0
    2. 0 3 4 5 = 12

  13. Rishi Malhotra 3 years ago

    sir compare between surds and factorial ke homework mein diye last (2nd) question mein doubt hain…sir uska solution de dijiye…thanx sir.

  14. Hem Shah 3 years ago

    1. Assume a=-c and and b=-d. Min | a+b+c+d|=0

    2. We have to use non-negative integers. And we can assume any one parameter as zero the equation will be reduced to Pythagoras triplet question so. a+b+c+d=0+5+3+4=12

    If we want to go further for only positive solutions. Minimum will be 1+8+4+7=20

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