GATE Paper Analysis IN 2019: GATE exam analysis for GATE Instrumentation paper with Answer Key and detailed video solutions.

Our experts provide detailed paper analysis about the topic-wise weightage, with GATE qualifying marks and help you understand the GATE 2019 exam trend with difficulty level.

With our detailed GATE 2019 Answer Key students can benchmark the performance and stay ahead of competition.

Do not forget to download GATE 2019 Answer Key for IN with Question Paper and Video Solutions.

In the given network
Initially, C_1 has 6 coulombs and C2 has a 0-coulomb charge when s is closed at t=0. The charge on C_2 at steady state is ________C

#gate2019answerkey #gatepaperanalysis #gateInstrumentation2019

GATE 2019 Answer Key:

GATE Score Calculator:

Railway Recruitment Board: GATE 2019 Aspirants can also increase their chance and get selected in RRB JE, get all the details for RRB exam preparation here —

For more details, visit our website and social handles as below:

1. Web:
2. Email: [email protected]
3. Like us:
4. Instagram –…
5. Blogs: Call us at 080-40611000


Fill this form and get best deals on " Coaching classes"

  • 100% genuine institutes aiming to help you ace studies
  • Get immediate response from the institutes
  • Compare institutes and pick only the best!
  • Feel free to choose the institute you like, and rest will be taken care of

Comments are closed.

  1. vishvesh patel 2 years ago

    Tough method kyo chose kiya…
    Jabki capasitor voltage equation se hota hai

  2. varun singh 2 years ago

    simply charge supplied equal to charge stored…get answer in one line

  3. vishal mishra 2 years ago

    Better go by Laplace approach…

  4. Kamal Tiwari 2 years ago


  5. sourav saini 2 years ago

    Cgarge conservation se 1min bhi nahi lagega

  6. koda raju 2 years ago

    It's a 1 Mark question?????

  7. shekhar patle 2 years ago

    Can be solve by Laplace easily

  8. Sutanu Goswami 2 years ago

    Sir laplace transform aur final value theorem se jaldi hoga. Thanku

  9. Shovan Deb 2 years ago

    Lengthy approach

  10. rahul babar 2 years ago

    Easy way se bhi aa Sakta

  11. shinibali mandal 2 years ago

    Plzz Provide solutions for control

  12. mir suhail 2 years ago

    I think, at time t=0- ,,switch is open, then how initial current will flow. Plz clarify it.

  13. HAPPY INDIA 2 years ago


  14. Thanks sir!!

  15. ANKIT SINGH 2 years ago

    laplace transform karo yaar,,

  16. praveen singh 2 years ago

    Q(0-) = Q(0+) then get V across parallel connection and then Q2(0+)= V * C2

  17. Gagan Malrha 2 years ago


  18. Subhabrata Pal 2 years ago

    in Gateforum answer key they give answer will be 0C….what is ri8 & wht is wrong?

  19. Just use
    V1(inf) = V2(inf) = (V1(0)C1 + V2(0)C2)/(C1+C2)
    Then q=C V2(inf)

GET UPTO 50%    OFF!
Verify Yourself

Log in with your credentials


Forgot your details?

Create Account