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     EduGorilla 
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    Total no. of possible outcomes = 12C3 = 220. Number of ways of selecting three defective bulbs from 6 defective bulbs = 6C3=20. Probability that the room is not lighted = 20/220=1/11. Probability that the room is lighted= 1-1/11=10/11.

    Options :-

    1. 5 /15

    2. 5/16

    3. 5/14

    4. 5/12

    5. None

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