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The equation of the circle which touches x-axis at (3, 0) and passes through (1, 4) is given by
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- x2 + y2 – 6x – 5y + 9 = 0
- x2 + y2 + 6x + 5y – 9 = 0
- x2 + y2 – 6x + 5y – 9 = 0
- x2 + y2 + 6x – 5y + 9 = 0
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