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     EduGorilla 
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    The equation of the circle which touches both the axes and the straight line 4x + 3y = 6 in the first quadrant and lies below it, is

    Options :-

    1. 4x2 + 4y2 – 4x – 4y + 1 = 0
    2. x2 + y2 – 6x – 6y + 9 = 0
    3. x2 + y2 – 6x – y + 9 = 0
    4. 4(x2 + y2 – x – 6y) + 1 = 0
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