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     EduGorilla 
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    Statement 1: ∼(p↔∼q)is equivalent to p↔q

    Statement 2 :∼(p↔∼q) is a tautology

    Options :-

    1. Both Statement 1 and Statement 2 are true and Statement 2 is a correct explanation for statement 1

    2. Both Statement 1and Statement 2 are true and Statement 2 is not a correct explanation for Statement 1

    3. Statement 1 is true but statement 2 is false

    4.  Clearly, ∼(p↔∼q)∼(p↔∼q) is not a tautology because it does not contain T in the column of its truth table. Also, ∼(p↔∼q)∼(p↔∼q) & p↔qp↔q have the same truth value

      Hence, option 'C' is correct.

      Statement 1 is false but Statement 2 is true

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