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On a line joining the points A(0, 4) and B(3, 0), a square ABCD is constructed on the side of the line away from the origin. Equation of the circle having centre at C and touching the x-axis is
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- x2 + y2 – 14x – 6y + 49 = 0
- x2 + y2 – 14x – 6y + 9 = 0
- x2 + y2 – 6x – 14y + 49 = 0
- x2 + y2 – 6x – 14y + 9 = 0
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