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In triangle ABC, CD is the bisector of the angle C, If

$\text{cos}\frac{\text{C}}{2}=\frac{1}{3}\text{and}\text{CD}=6$, then the value of

$\left(\frac{1}{\text{a}}+\frac{1}{\text{b}}\right)\text{.}$(Where , and are the lengths of the sides opposite to Angles A, B & C respectively)

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