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     EduGorilla 
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    In a triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular from B meets the side AC at D. A circle is drawn with radius BD and centre B. If the circle cuts AB and BC respectively at P and Q, then AP : QC is equal to

    Options :-

    1. 3 : 8
    2. 3 : 2
    3. 4 : 1
    4. 2 : 5
    5. 1 : 1
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Reply To: In a triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular from B meets the side AC at D. A circ….
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