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EduGorilla
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Four children A, B, C & D have some chocolates each.

A gives B as many as B already has, he gives C twice of what C already has, and he gives D thrice of what D already has.
Now, D gives 1/8th of his chocolates to B.
Then, A gives 10% of the chocolates he now has to C and 20% to B.
Finally, all of them have 35 chocolates each.

What is the number of chocolates each had in the beginning?

### Options :-

1. A - 110, B - 10, C - 10, D - 10
2. A - 90, B - 20, C - 20, D - 10
3. A - 70, B - 25, C - 25, D - 20
4. A - 125, B - 5, C - 5, D - 5
5. None of these
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