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     EduGorilla 
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    Four children A, B, C & D have some chocolates each.

    A gives B as many as B already has, he gives C twice of what C already has, and he gives D thrice of what D already has.
    Now, D gives 1/8th of his chocolates to B.
    Then, A gives 10% of the chocolates he now has to C and 20% to B. 
    Finally, all of them have 35 chocolates each.

    What is the number of chocolates each had in the beginning?

    Options :-

    1. A - 110, B - 10, C - 10, D - 10
    2. A - 90, B - 20, C - 20, D - 10
    3. A - 70, B - 25, C - 25, D - 20
    4. A - 125, B - 5, C - 5, D - 5
    5. None of these
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Reply To: Four children A, B, C & D have some chocolates each.A gives B as many as B already has, he gives….
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