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     EduGorilla 
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    For what value of k, the circles x2 + y2  4x   ky 12 = 0 and x2 + y2 + 6x + 4y  12 = 0 cut orthogonally?

    Options :-

    1. k = 3
    2. k = 4
    3. k = 6
    4. k = - 2
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Reply To: For what value of k, the circles x2 + y2 – 4x  – ky -12 = 0 and x2 + y2 + 6x + 4y -&n….
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