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     EduGorilla 
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    Consider the following program segment:
                {
                int n = 1;
               
                float x, term;            float sum = 1;
                term = 1;
                while (n < 51)
                {
                            term * = – x * x/ (n * (n + 1));
                            sum + = term;
                            n + = 2;
                            }
                }
    For a given x, the valve of sum approximates the function

    Options :-

    1. sin x
    2. cos x
    3. e–x
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