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     EduGorilla 
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    A train A of length 300 meters can cross a pole in 14.4 seconds and that train can cross a car running in opposite direction in 9 seconds, then what is the time taken by car to cross a bridge of length double of the length of train A with 4/3 of its original speed?

    Given below are the steps involved. Arrange them in the sequential order.

    A) Length of bridge = 2 * 300 = 600 meters

    B) Speed of train A = (300/14.4) * (18/5) = 75 km/h

    C) Time taken by car to cross the bridge = (600/45) * (18/5) = 48 seconds

    D) Changed speed of car = (4/3) * 45 = 60 km/h

    E) Speed of car = [(300/9) * (18/5)] – 75 = 45 km/h

    Options :-

    1. ADEBC

    2. CEADB

    3. BEADC

    4. EADCB

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