A capacitor of capacitance C can be charged (with the help of a resistance R) by a voltage source V,….

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A capacitor of capacitance C can be charged (with the help of a resistance R) by a voltage source V, by closing switch S₁ while keeping switch S₂ open (see the figure). The capacitor can be connected in series with an inductor L by closing switch S₂ and opening switch S₁.

Initially, the capacitor was uncharged. Now, switch S₁ is closed and S₂ is kept open. If time constant of this circuit is τ, then

Options :-

1. after time interval τ, charge on the capacitor is CV/2
2. after time interval 2τ, charge on the capacitor is CV(1 - e^-2)
3. the work done by the voltage source will be half of the heat dissipated when the capacitor is fully charged
4. after time interval 2τ, charge on the capacitor is CV(1 - e^-1)

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Answer/ Explanation

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