Question: Sequence P is defined by p(n) = p(n–1) +3, p(1) = 11, Sequence Q is defined as q(n) = q(n–1) – 4, q(3) = 103. If p(k) greater than q(k+2), what is the smallest value k can take?

A) 6
B) 11
C) 14
D) 15

For more CAT questions from Progressions, visit –

For CAT level Questions and video solutions – and visit
For 2IIM Question Bank –

Pump up your CAT Preparation with 2IIM Online CAT Course!
View 20% of the Course for Free.
Click the link below and Sign up as Trail User to Start your CAT reparation.

To join our facebook group, visit

Post your feedback –

Visit to know what the students have said.

Go to for an amazing learning experience on your Android phone

For more CAT Level questions. Visit our free Question bank –

Subscribe and Like and Share! Best Wishes.


Fill this form and get best deals on " Coaching classes"

  • 100% genuine institutes aiming to help you ace studies
  • Get immediate response from the institutes
  • Compare institutes and pick only the best!
  • Feel free to choose the institute you like, and rest will be taken care of
Verify Yourself

Log in with your credentials


Forgot your details?

Create Account