Question: 2x + 5y = 103. Find the number of positive integers, x, y, that satisfy this equation.
(a) 9
(b) 10
(c) 12
(d) 20


This says that when you subtract a multiple of 5 from 103, you get an even number. You have to subtract an odd multiple of 5 from 103 in order to get an even number. There are 20 multiples of 5 till 100, ten of which are odd. (Note that you cannot subtract 105, or higher multiples as they result in a negative value for x.)
So, y can have ten integer values. x also has 10 integer values, each corresponding to a particular value of y.
y = 1, gives us a potential value for x, so do y = 3, 5, 7….19. y can take 10 values totally.

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Comments are closed.

  1. Ravikant Yadav 3 years ago

    first view

  2. Good trick sir!

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